The number of optical isomers possible for Cr C 2 O 4 3 3 - is:

The number of optical isomers possible for

{[Cr {(C_{2} O_{4})}_{3}]}^{3 -}

is:

Solution

The number of optical isomers for ${[Cr {(C_{2} O_{4})}_{3}]}^{3 -}$ is two ( $d$ -isomer and $l$ -isomer).

Asked in: JEE Main 2021 (27 Aug Shift 2)

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