The number of neutrons emitted when ${ }_{92}^{235} \mathrm{U}$ undergoes controlled nuclear fission to ${ }_{54}^{142} \mathrm{Xe}$ and ${ }_{38}^{90} \mathrm{Sr}$ is

Question

Aicharya · Accepted Answer

${ }_{92} \mathrm{U}^{235} \longrightarrow{ }_{54} \mathrm{Xe}^{142}+{ }_{38} \mathrm{Sr}^{90}+3{ }_0 n^1$ Nuclear chemistry Basic application II

The number of neutrons emitted when ${ }_{92}^{235} \mathrm{U}$ undergoes controlled nuclear fission to ${…

Solution