The number of natural numbers less than 500 in which no two digits are repeated is
- $374$
- $376$
- $378$
- $380$
Solution

4 ways $=4$ number $(1,2,3,4)$ Now number of 2 digit natural numbers less than 500 in which no. of two digits are repeated $=9 \times 9=81$ Now number of 1 digit natural number less than $500=9$ Therefore required number of digits $=288+81+9=378$
Asked in: AP EAMCET 2023 (19 May Shift 1)