The number of lone pairs of electrons present on $\mathrm{Xe}$ in $\mathrm{XeF}_4$ is
The number of lone pairs of electrons present on $\mathrm{Xe}$ in $\mathrm{XeF}_4$ is
$3$
$4$
$1$
$2$
Solution
Xe in ground state $\longrightarrow \ldots 5 s^2, 5 p^6, 5 d^6$
$X_e$ in IInd excited state $\longrightarrow \ldots 5 s^2, 5 p^4, 5 d^2$
$\longrightarrow \ldots .5 s^2, 5 p^4, 5 d^2$
Number of lone pairs $=2$
Number of bond pairs $=4$
