The number of lone pairs of electrons on the central atom of $\mathrm{BrF}_5, \mathrm{XeO}_3, \mathrm{SO}_2$…
The number of lone pairs of electrons on the central atom of $\mathrm{BrF}_5, \mathrm{XeO}_3, \mathrm{SO}_2$ respectively are
- $1,1,2$
- $1,2,2$
- $2,2,1$
- $1,1,1$
Solution
$\begin{array}{|c|c|c|c|}\hline \text{Molecule} & \begin{array}{c} \text{Valence} \\ \text{electron of CM} \end{array} & \text{Bond pair} & \begin{array}{c} \text{Lone} \\ \text{pair} \end{array} \\ \hline \mathrm{BrF}_5 & 7 & 5 & 1 \\ \hline \mathrm{XeO}_3 & 8 & 3 & 1 \\ \hline \mathrm{SO}_2 & 6 & 2 & 1 \\ \hline\end{array}$
Asked in: AP EAMCET 2024 (22 May Shift 2)
Practice more Chemical Bonding and Molecular Structure questions on Aicharya