The number of isomers possible for a dibromo derivate (Molecular weight $=186 \mathrm{u})$ of an alkene is…

The number of isomers possible for a dibromo derivate (Molecular weight $=186 \mathrm{u})$ of an alkene is $(\mathrm{Br}=80 \mathrm{u})$
  1. 2
  2. 3
  3. 4
  4. 6

Solution

Molecular weight of dibromo derivative $=186 \mathrm{u}$
Possible structures will be

Asked in: AP EAMCET 2024 (22 May Shift 1)

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