The number of $\mathrm{H}^{+}$ions present in $1 \mathrm{~mL}$ of a solution whose $\mathrm{pH}$ is 13

The number of $\mathrm{H}^{+}$ions present in $1 \mathrm{~mL}$ of a solution whose $\mathrm{pH}$ is 13
  1. $6.022 \times 10^{10}$
  2. $6.022 \times 10^{7}$
  3. $6.022 \times 10^{20}$
  4. $6.022 \times 10^{23}$

Solution

$\mathrm{pH}=13$ $\begin{aligned} {[\mathrm{H}]^{+} } &=10^{-\mathrm{pH}}=10^{-13} \mathrm{~mol} \mathrm{~l}^{-1} \\ & \Rightarrow 1000 \mathrm{~mL} \text {solution contains } \\ &=10^{-13} \times 6.022 \times 10^{23} \mathrm{H}^{+} \text {ions } \\ &=6.022 \times 10^{10} \mathrm{H}^{+} \text {ions } \end{aligned}$ $1 \mathrm{~mL}$ solution contains $=\frac{6.022 \times 10^{10}}{1000}=6.022 \times 10^{7} \mathrm{H}^{+} \text {ions. }$

Asked in: TEST SERIES MHT-CET Full Test 6

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