The number of geometric isomers that can exist for square planar P t C l p y N H 3 N H 2 O H + is (py =…

The number of geometric isomers that can exist for square planar PtClpyNH3NH2OH+ is (py = pyridine):
  1. 6
  2. 2
  3. 3
  4. 4

Solution

Complex with general formula [Mabcd]+ square planar complex can have three isomers.

Asked in: JEE Main 2015 (04 Apr)

Practice more Coordination Compounds questions on Aicharya