The number of four-digit numbers formed by using the digits $0,2,4,5$ and which are not divisible by 5 , is
- $10$
- $8$
- $6$
- $4$
Solution

$3 \times 3 \times 2 \times 1=18$ Total number of four-digit numbers that are divisible by $5=$ Number which ends with 0 and 5 . Number ends with 0 .

$3 \times 2 \times 1 \times 1=6$ Number ends with 5 .

$2 \times 2 \times 1 \times 1=4$ $\therefore \quad$ Total number of four digits numbers that are not divisible by $5=18-(6+4)=8$
Asked in: AP EAMCET 2015