The number of elements among \(\mathrm{O}, \mathrm{Cl}, \mathrm{F}, \mathrm{N}\), \(\mathrm{P}, \mathrm{Sn},…
The number of elements among \(\mathrm{O}, \mathrm{Cl}, \mathrm{F}, \mathrm{N}\), \(\mathrm{P}, \mathrm{Sn}, \mathrm{Ti}, \mathrm{K}, \mathrm{Sc}\), which show more than one non-zero oxidation state is
2
3
6
8
Solution
Sodium (+1), scandium (+3) and fluorine \((-1)\) show only one non-zero oxidation state.
The oxidation states of oxygen are \(-1,-2\) and +2
The oxidation states of chlorine range from -1 to +7.
The oxidation states of nitrogen and phosphorus range from -3 to +5.
The oxidation states of tin range from +2 to +4.
The oxidation states of scandium is +3. Scandium \((Z=21)\) does not exhibit variable oxidation states and yet it is regarded as a transition element because scandium has partially filled \(d\)-orbitals in the ground state.
The oxidation states of titanium are \(+2,+3,+4\) respectively.
Hence, the correct option is (c).