The number of electrons involved in the reduction of one nitrate ion to hydrazine is
- 8
- 5
- 3
- 7
Solution
So, for reduction of 1 mole of $\mathrm{NO}_{3}^{-}$ number of electrons required is 7 .
Asked in: JEE-TOPICTESTS-CHEMISTRY
So, for reduction of 1 mole of $\mathrm{NO}_{3}^{-}$ number of electrons required is 7 .