The number of $\mathrm{d}$ - electrons in $\mathrm{Cr}^{3+}$ ion $(\mathrm{Z}=24)$ is

Question

Aicharya · Accepted Answer

$\mathrm{Cr}=[\mathrm{Ar}] 3 \mathrm{~d}^5 4 \mathrm{~s}^1$ so $\mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 \mathrm{~d}^3$ $\Rightarrow \quad$ Number of d-electrons $=3$

The number of $\mathrm{d}$ - electrons in $\mathrm{Cr}^{3+}$ ion $(\mathrm{Z}=24)$ is

Solution