The number of $d$ electrons in Fe is equal to which of the following? i. Total number of ' $s$ ' electrons…
The number of $d$ electrons in Fe is equal to which of the following?
i. Total number of ' $s$ ' electrons of Mg
ii. Total number of ' $p$ ' electrons of Cl
iii. Total number of ' $p$ ' electrons of Ne The correct option is
i, ii only
ii, iii only
i, iii only
$\mathrm{i}, \mathrm{ii}, \mathrm{iii}$
Solution
Electronic configuration of $\mathrm{Fe}=[\mathrm{Ar}] 3 \mathrm{~d}^6 4 \mathrm{~s}^2$
$\therefore \quad$ iron have 6 electron in d orbital
Electronic configuration
$\mathrm{Mg}: 1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6 3 \mathrm{~s}^2$
$\mathrm{Cl}:[\mathrm{Ne}] 3 \mathrm{~s}^2 3 \mathrm{p}^5$
$\mathrm{Ne}: 1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^6$
$\therefore \quad$ Ne have 6 electron in p orbital which is same as Fe electron in d orbital and Mg have also 6 electron in all 's' orbital. Hence (i) and (iii) are correct.