The number of electric lines of force that radiate outwards from one coulomb of charge in vacuum is

The number of electric lines of force that radiate outwards from one coulomb of charge in vacuum is
  1. $1.13 \times 10^{11}$
  2. $1.13 \times 10^{10}$
  3. $0.61 \times 10^{11}$
  4. $0.61 \times 10^{9}$

Solution

Here, $q=1 \mathrm{C}, \varepsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} N^{-1} \mathrm{~m}^{-2}$
Number of lines of force $=$ Electric force $=\frac{q}{\varepsilon_{0}}=\frac{1}{8.85 \times 10^{-12}}=1.13 \times 10^{11}$ *

Asked in: JEE Mains - Electrostatics - Test 2

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