The number of different ways of preparing a garland using 6 distinct white roses and 5 distinct red roses such that no two red roses come together is

Question

Aicharya · Accepted Answer

Given, White roses $=6$ Red roses $=5$ $	herefore \quad$ Total number of ways for making garlands such that no two red roses come together is $ =\frac{6 ! 	imes 5 !}{2}=43200 $

The number of different ways of preparing a garland using 6 distinct white roses and 5 distinct red roses…

Solution