The number of different ways of preparing a garland by using 6 distinct white roses and 6 distinct red roses…
The number of different ways of preparing a garland by using 6 distinct white roses and 6 distinct red roses such that no two red roses come together is
43200
86400
59200
76800
Solution
Given, 6 distinct white roses and 6 distinct red roses
So, required number of ways $=\frac{6!\times 5!}{2}=\frac{86400}{2}=43200$
