The number of complexes from the following with no electrons in the \(t_2\) orbital is \(\qquad\)…

The number of complexes from the following with no electrons in the \(t_2\) orbital is \(\qquad\) \(\mathrm{TiCl}_4,\left[\mathrm{MnO}_4\right]^{-},\left[\mathrm{FeO}_4\right]^{2-},\left[\mathrm{FeCl}_4\right]^{-},\left[\mathrm{CoCl}_4\right]^{2-}\)
  1. 1
  2. 4
  3. 3
  4. 2

Solution

$\begin{array}{ll}\mathrm{TiCl}_4 \Rightarrow \mathrm{Ti}^{+4} & \mathrm{e}^0 \mathrm{t}_2^0 \\ \mathrm{MnO}_4^{-} \Rightarrow \mathrm{Mn}^{+7} & \mathrm{e}^0 \mathrm{t}_2^0 \\ \mathrm{FeO}_4^{2-} \Rightarrow \mathrm{Fe}^{+6} & \mathrm{e}^2 \mathrm{t}_2^0 \\ \mathrm{FeCl}_4^{2-} \Rightarrow \mathrm{Fe}^{+2} & \mathrm{e}^3 \mathrm{t}_2^3 \\ \mathrm{CoCl}_4^{2-} \Rightarrow \mathrm{Co}^{+2} & \mathrm{e}^4 \mathrm{t}_2^3\end{array}$

Asked in: JEE Main 2024 (05 Apr Shift 2)

Practice more Coordination Compounds questions on Aicharya