The number of atoms in 0.1 mole of a triatomic gas is $\left(\mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23}…
The number of atoms in 0.1 mole of a triatomic gas is $\left(\mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23} \mathrm{~mol}^{-1}\right)$
- $6.026 \times 10^{22}$
- $1.806 \times 10^{23}$
- $3.600 \times 10^{23}$
- $1.800 \times 10^{22}$
Solution
Number of atoms $=$ number of moles $\times \mathrm{N}_{\mathrm{A}} \times$ atomicity
$\begin{aligned}
& =0.1 \times 6.02 \times 10^{23} \times 3 \\
& =1.806 \times 10^{23} \text { atoms }
\end{aligned}$
Asked in: NEET 2010 (Screening)
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