The number of all possible solutions of the equation $\mathrm{z}^3+\overline{\mathrm{z}}=0$ is
The number of all possible solutions of the equation $\mathrm{z}^3+\overline{\mathrm{z}}=0$ is
- 4
- 5
- 3
- 6
Solution
$
\begin{aligned}
& \text { Given that } z^3+\bar{z}=0 \Rightarrow z^3=-\bar{z} \\
& \Rightarrow|z|^3=|-\bar{z}|=|z| \Rightarrow|z|\left(|z|^2-1\right)=0 \\
& |z|=0 \text { or }|z|^2=1 \Rightarrow z \bar{z}=1 \Rightarrow \bar{z}=\frac{1}{z} \\
& \therefore z^3+\bar{z}=0 \Rightarrow z^3+\frac{1}{z}=0 \\
& \Rightarrow z^4+1=0 \rightarrow 4 \text { solution } \\
& |z|=0 \rightarrow \text { one solution }
\end{aligned}
$
Total 5 solution
Asked in: AP EAMCET 2023 (15 May Shift 1)
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