The number density of free electrons in copper is nearly 8 × 10 28   m - 3 . A copper wire has its…

The number density of free electrons in copper is nearly 8×1028 m-3. A copper wire has its area of cross-section =2×10-6 m2 and is carrying a current of 3.2 A. The drift speed of the electrons is _____×10-6 m s-1.

Solution

The formula to calculate the current through any conductor is given by

I=nAevd   ...1

Substitute the values of the given parameters into equation (1) and solve to calculate the required drift velocity of the electrons.

3.2=8×1028×2×10-6×1.6×10-19×vdvd=3.216×1.6×1000 m s-1=125×10-6 m s-1

Asked in: JEE Main 2023 (08 Apr Shift 2)

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