The number 3798125P369 is divisible by 7. What is the value of the digit P?

The number 3798125P369 is divisible by 7. What is the value of the digit P?
  1. 1
  2. 6
  3. 7
  4. 9

Solution

Group the digits into triplets from the right: (37)(981)(25P)(369). The alternating sum for divisibility by 7 gives $369 - 25P + 981 - 37 = 1313 - 25P$. For this to be divisible by 7, with 25P between 250 and 259, we need 25P = 256, which makes $1313 - 256 = 1057 = 7 \times 151$. Hence P = 6.

Asked in: CSAT 2021

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