The null point of a potentiometer with a cell of emf $\varepsilon$ is obtained at a distance $l$ on the wire…

The null point of a potentiometer with a cell of emf $\varepsilon$ is obtained at a distance $l$ on the wire, then
  1. $\varepsilon \propto l$
  2. $\varepsilon \propto l^2$
  3. $\varepsilon \propto \frac{1}{l}$
  4. $\varepsilon \propto \frac{1}{l^2}$

Solution

As we know, electric field, $E=-\frac{d V}{d r}$ Hence, emf $\varepsilon$ is also directly proportional to $l$ i.e., $\varepsilon \propto l$.

Asked in: AP EAMCET 2021 (25 Aug Shift 2)

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