The negation of the statement, $\exists x \in A$ such that $x+5>8$ is
The negation of the statement, $\exists x \in A$ such that $x+5>8$ is
$\forall x \in A, \quad x+5 \geq 8$
$\forall x \in A, \quad x+5 \leq 8$
$\forall x \in A, \quad x+5>8$
$\exists x \in A$ such that $x+5 < 8$
Solution
While doing negation we replace $\exists$ by $\forall$ and $>$ by $\leq$.
So required statement is $\forall \mathrm{x} \in \mathrm{A}$ such that $\mathrm{x}+5 \leq 8$