The negation of inverse of $\sim p \rightarrow q$ is
The negation of inverse of $\sim p \rightarrow q$ is
$\sim \mathrm{p} \wedge \mathrm{q}$
$\sim \mathrm{q} \rightarrow \mathrm{p}$
$p \wedge(\sim q)$
$\mathrm{p} \wedge \mathrm{q}$
Solution
We have $\sim \mathrm{p} \rightarrow \mathrm{q}$
Inverse of given statement is
$\sim(\sim \mathrm{p}) \rightarrow \sim \text { q i.e. } \mathrm{p} \rightarrow \sim \mathrm{q}$
Negation of inverse of given statement is $\sim(p \rightarrow \sim q)$
$\equiv \sim(\sim p \vee \sim q) \equiv p \wedge q$