The natural number m , for which the coefficient of x in the binomial expansion of x m + 1 x 2 22 is 1540, is

The natural number m, for which the coefficient of x in the binomial expansion of  xm+1x222 is 1540, is

Solution

The general term in the binomial expansion,

Tr+1=Cr22xm22-rx-2r

Tr+1=Cr22xm(22-r)-2r

For the coefficient of x

22 m-m r-2 r=1

22 m-1=r(m+2)

r=22m-1m+2

r=22m+44-45m+2

r=22-3.3.5m+222-r=3·3·5m+2

Since, Cr22=C22-r22

So possible values of m=1,3,7,13,43, but C322=154022-r=3m=13

Asked in: JEE Main 2020 (05 Sep Shift 1)

Practice more Binomial Theorem questions on Aicharya