The most general value of $\theta$ which satisfies both the equations $\tan 8=-1$ and $\cos…
The most general value of $\theta$ which satisfies both the equations $\tan 8=-1$ and $\cos \theta=\frac{1}{\sqrt{2}}$ is
- $n \pi+\frac{7 \pi}{4}$
- $2 n \pi+\frac{7 \pi}{4}$
- $n \pi+(-1)^n \frac{7 \pi}{4}$
- $\frac{7 n \pi}{4}$
Solution
Given trigonometric equations are
$\tan \theta=-1$
and
$\cos \theta=\frac{1}{\sqrt{2}}$
$\begin{array}{ll}\Rightarrow & \sin \theta=-1 / \sqrt{2} \\ \Rightarrow & \sin \theta=\sin \frac{7 \pi}{4} \\ \therefore & \theta=2 n \pi+\frac{7 \pi}{4}\end{array}$
Asked in: AP EAMCET 2011
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