The moment of inertia of a uniform circular disc of radius $R$ and mass $M$ about an axis passing from the…
The moment of inertia of a uniform circular disc of radius $R$ and mass $M$ about an axis passing from the edge of the disc and normal to the disc is:
$M R^2$
$\frac{1}{2} M R^2$
$\frac{3}{2} M R^2$
$\frac{7}{2} M R^2$
Solution
M.I. of disc about its normal $=\frac{1}{2} M R^2$
M.I. about its one edge $=M R^2+$ $\frac{M R^2}{2}$
$\therefore \quad \text { M.I. }=\frac{3}{2} M R^2$