The moment of inertia of a uniform circular disc (figure) is maximum about an axis perpendicular to the disc…

The moment of inertia of a uniform circular disc (figure) is maximum about an axis perpendicular to the disc and passing through
  1. $B$
  2. $C$
  3. $D$
  4. $A$

Solution

According to parallel axis theorem of the moment of Inertia
$
I=I_{\mathrm{cm}}+m d^{2}
$
$d$ is maximum for point $B$ so $I_{\max }$ about $B$

Asked in: JEE Mains - Rotational Motion - Test 1

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