The moment of inertia of a uniform circular disc (figure) is maximum about an axis perpendicular to the disc…
The moment of inertia of a uniform circular disc (figure) is maximum about an axis perpendicular to the disc and passing through
- $B$
- $C$
- $D$
- $A$
Solution
According to parallel axis theorem of the moment of Inertia
$
I=I_{\mathrm{cm}}+m d^{2}
$
$d$ is maximum for point $B$ so $I_{\max }$ about $B$
Asked in: JEE Mains - Rotational Motion - Test 1
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