The moment of inertia of a body about the given axis, rotating with angular velocity $1 \mathrm{rad} /…
The moment of inertia of a body about the given axis, rotating with angular velocity $1 \mathrm{rad} / \mathrm{s}$ is numerically equal to ' $\mathrm{P}$ ' times its rotational kinetic energy. The value of ' $\mathrm{P}$ ' is
$\frac{1}{4}$
$\frac{1}{2}$
$2$
$1$
Solution
The angular velocity
$\begin{aligned}
& \omega=1 \mathrm{rad} / \mathrm{s} \\
& I=P \cdot\left(\frac{1}{2} I \omega^2\right) \\
& \therefore P=2
\end{aligned}$