The molecules of a given mass of gas have RMS velocity of 200 m s - 1 at 27 o C and 1.0 × 10 5 N m - 2…

The molecules of a given mass of gas have RMS velocity of 200  s-1 at 27oC and 1.0×105 m-2 pressure. When the temperature and pressure of the gas are respectively, 127oC and 0.05×105 m-2, the r.m.s. velocity of its molecules in s-1 is:
  1. 1002
  2. 4003
  3. 10023
  4. 1003

Solution

RMS speed of molecules is VRMS=3RTM, where R is universal gas constant, T is absolute temperature and M is molar mass of gas.
So it depends only on temperature, VrmsT
V1V2=T1T2200V2=300400
200V2=32V2=4003 m sec-1

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Asked in: NEET 2016 (Phase 1)

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