The mole fraction of water in $20 \%$ aqueous solution (By weight) of $\mathrm{H}_{2} \mathrm{O}_{2}$ is
The mole fraction of water in $20 \%$ aqueous solution (By weight) of $\mathrm{H}_{2} \mathrm{O}_{2}$ is
- $\frac{77}{68}$
- $\frac{68}{77}$
- $\frac{20}{80}$
- $\frac{80}{20}$
Solution
Mole fraction of $\mathrm{H}_{2} \mathrm{O}=$ $\frac{\frac{80}{18}}{\frac{80}{18}+\frac{20}{34}}=\frac{68}{77}$
Asked in: JEE-TOPICTESTS-CHEMISTRY
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