The mole fraction of a solute in a solution is 0 . 1 . At 298   K , the molarity of this solution is…

The mole fraction of a solute in a solution is 0.1. At 298 K, the molarity of this solution is the same as its molality. The density of this solution at 298 K is 2.0 g cm–3. The ratio of the molecular weights of the solute and solvent, MWsoluteMWsolvent, is:

Solution

1 mole solution has 0.1 mole solute and 0.9 mole solvent.
Let M1=Molar mass of solute
M2=Molar mass of solvent
Molality, m=0.10.9 M2×1000…..1
Molarity, M=0.10.1 M1+0.9 M2×2×1000…..2
∵m=M
⇒0.1×10000.9 M2=2000.1 M1+0.9 M2
⇒M1M2=9
 

Asked in: JEE Advanced 2016 (Paper 1)

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