The molarity of the solution when $4.9 \mathrm{~g}$ of $\mathrm{H}_2 \mathrm{SO}_4$ dissolved in $250…

The molarity of the solution when $4.9 \mathrm{~g}$ of $\mathrm{H}_2 \mathrm{SO}_4$ dissolved in $250 \mathrm{~mL}$ of solution is
  1. $0.1$
  2. $0.2$
  3. $0.3$
  4. $0.4$

Solution

Molarity $=\frac{\frac{4.9 \mathrm{~g}}{98.0 \mathrm{~g} \mathrm{~mol}^{-1}}}{0.250 \mathrm{~L}}=0.2 \mathrm{~mol} \mathrm{~L}^{-1}$

Asked in: AP EAMCET 2023 (18 May Shift 1)

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