The molarity of the solution prepared by dissolving $6.3 g$ of oxalic acid $(H_{2} C_{2} O_{4} \cdot 2 H_{2} O)$ in $250 mL$ of water in $mol L^{- 1}$ is $x \times 10^{- 2} .$ The value of $x$ is _________ . (Nearest integer)
[Atomic mass : $H : 1.0, C : 12.0, 0 : 16.0 J$ ]

Question

The molarity of the solution prepared by dissolving

6.3 g

of oxalic acid

(H_{2} C_{2} O_{4} \cdot 2 H_{2} O)

in

250 mL

of water in

mol L^{- 1}

is

x \times 10^{- 2} .

The value of

x

is _________ . (Nearest integer)
[Atomic mass :

H : 1.0, C : 12.0, 0 : 16.0 J

]

Aicharya · Accepted Answer

M = W solute &#215; 1000 GMM solute &#215; V ml = 6 . 3 &#215; 1000 126 &#215; 250 = 0 . 2 &#160; M = 20 &#215; 10 - 2 So X = 20

The molarity of the solution prepared by dissolving 6 . 3   g of oxalic acid H 2 C 2 O 4 · 2 H 2 O…