The molarity of a $70 \%$ (mass $/$ mass) aqueous solution of a monobasic acid $(\mathrm{X})$ is __________…
[Given: Density of aqueous solution of (X) is $1.25 \mathrm{~g} \mathrm{~mL}^{-1}$
Molar mass of the acid is $70 \mathrm{~g} \mathrm{~mol}^{-1}$ ]
Solution
Volume of solution $=\frac{100}{1.25}=80 \mathrm{~mL}$
$\begin{aligned}
& M=\frac{1}{80} \times 1000=12.5 \\
& M=125 \times 10^{-1}
\end{aligned}$
Asked in: JEE Main 2025 (28 Jan Shift 1)
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