The Molarity $(\mathrm{M})$ of an aqueous solution containing $5.85 \mathrm{~g}$ of NaCl in $500 \mathrm{~mL}$ water is : (Given : Molar Mass $\mathrm{Na}: 23$ and $\mathrm{Cl}: 35.5 \mathrm{gmol}^{-1}$ )

Question

Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{M}=\frac{\mathrm{n}_{\mathrm{NaCl}}}{\left.\mathrm{V}_{\mathrm{sol}} 	ext { (in } \mathrm{L}ight)} \ & \mathrm{M}=\frac{\frac{5.85}{58.5}}{0.5}=0.2 \mathrm{M}\end{aligned}$

The Molarity \((\mathrm{M})\) of an aqueous solution containing \(5.85 \mathrm{~g}\) of NaCl in \(500…

Solution