The molar conductivity of 0.01 M acetic acid at $25^{\circ} \mathrm{C}$ is $16.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ and its molar conductivity at zero concentration is $390: 7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$. What is its degree of dissociation?

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Aicharya · Accepted Answer

$\alpha=\frac{16.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}{390.7 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}}=0.0422$

The molar conductivity of 0.01 M acetic acid at $25^{\circ} \mathrm{C}$ is $16.5 \Omega^{-1} \mathrm{~cm}^2…

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