The minimum value of f x = a a x + a 1 - a x , where a ,   x ∈ R and a > 0 , is equal to:

The minimum value of fx=aax+a1-ax, where a, x∈R and a>0, is equal to:
  1. a+1
  2. 2a
  3. a+1a
  4. 2a

Solution

A.M.≥G.M.

fx=aax+a1-ax=aax+aaax≥2a

Asked in: JEE Main 2021 (25 Feb Shift 2)

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