The minimum horizontal speed with which a body must be projected, so that it goes around a smooth vertical…
The minimum horizontal speed with which a body must be projected, so that it goes around a smooth vertical circular track of radius \(4 \mathrm{~m}\) is \(\left(g=9.8 \mathrm{~ms}^{-2}\right)\)
\(7 \mathrm{~ms}^{-1}\)
\(14 \mathrm{~ms}^{-1}\)
\(0.7 \mathrm{~ms}^{-1}\)
\(1.4 \mathrm{~ms}^{-1}\)
Solution
Radius of circular vertical track,
\(r=4 \mathrm{~m}, g=9.8 \mathrm{~ms}^{-2}\)
\(\therefore\) Minimum horizontal speed at lowest point to complete the revolution in vertical circle,
\(v=\sqrt{5 g r}=\sqrt{5 \times 9.8 \times 4}=\sqrt{196}=14 \mathrm{~ms}^{-1}\)