The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly :

The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly :
  1. 1.5 eV
  2. 13.6 eV
  3. 1.9 eV
  4. 12.1 eV

Solution

For Balmer series, transition is from n=3,4,5,6, etc to n=2.

For transition to n=2, the minimum state to transition from is n=3

Therefore, energy required ΔE=E3-E1=-13.69--13.6=12.1eV

Asked in: JEE Main 2024 (01 Feb Shift 1)

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