The micro-organisms double themselves in 3 hours. Assuming that the quantity increases at a rate…

The micro-organisms double themselves in 3 hours. Assuming that the quantity increases at a rate proportional to it self, then the number of times it multiplies themselves in 18 years is
  1. 32
  2. 64
  3. 128
  4. 40

Solution

Let initial number of microorganisms be $\mathrm{N}$. The microorganisms double themselves in 3 hours. $\therefore$ Number of microorganisms after 3 hours $=2 \times \mathrm{N}=2 \mathrm{~N}$ o hours $=2 \times 2 \mathrm{~N}=4 \mathrm{~N}$ 9 hours $=2 \times 4 \mathrm{~N}=8 \mathrm{~N}$ 12 hours $=2 \times 8 \mathrm{~N}=16 \mathrm{~N}$ 15 hours $=2 \times 16 \mathrm{~N}=32 \mathrm{~N}$ 18 hours $=2 \times 32 \mathrm{~N}=64 \mathrm{~N}$

Asked in: MHT CET 2020 (16 Oct Shift 2)

Practice more Differential Equations questions on Aicharya