The mean of the numbers obtained on throwing a die having written 1 on three faces, 2 on two faces and 5 on one face is

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Aicharya · Accepted Answer

Probability of getting $1=\frac{3}{6}=\frac{1}{2}$ Probability of getting $2=\frac{2}{6}=\frac{1}{3}$ Probability of getting $5=\frac{1}{6} 	herefore \quad$ Mean $=\Sigma \mathrm{p}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}=2$ $\begin{array}{|l|l|l|} \hline \mathrm{x}_{\mathrm{i}} & \mathrm{p}_{\mathrm{i}} & \mathrm{p}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}} \ \hline 1 & 1 / 2 & 1 / 2 \ \hline 2 & 1 / 3 & 2 / 3 \ \hline 5 & 1 / 6 & 5 / 6 \ \hline & 	ext{Total} & 2 \ \hline \end{array}$

The mean of the numbers obtained on throwing a die having written 1 on three faces, 2 on two faces and 5 on…

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