The mean of numbers $a, b, 8,5,10$ is 6 and their variance is 6.80. Then $\operatorname{Tan}^{-1}…

The mean of numbers $a, b, 8,5,10$ is 6 and their variance is 6.80. Then $\operatorname{Tan}^{-1} \frac{1}{a}+\operatorname{Tan}^{-1} \frac{1}{b}=$
  1. $\operatorname{Tan}^{-1} \frac{7}{12}$
  2. $\operatorname{Tan}^{-1}\left(-\frac{7}{11}\right)$
  3. $\operatorname{Tan}^{-1} \frac{11}{7}$
  4. $\operatorname{Tan}^{-1} \frac{7}{11}$

Solution

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Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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