The mean of $5$ numbers is $20$. If one number $32$ is removed, the mean of the remaining $4$ numbers is:
The mean of $5$ numbers is $20$. If one number $32$ is removed, the mean of the remaining $4$ numbers is:
- $15$
- $17$
- $18$
- $20$
Solution
Sum of $5$ numbers $= 5\times 20 = 100$. Sum of remaining $4 = 100-32 = 68$. New mean $= \dfrac{68}{4} = 17$.
Asked in: IMO
Practice more DATA HANDLING questions on Aicharya