The mean free path for a gas, with molecular diameter d and number density n can be expressed as:

The mean free path for a gas, with molecular diameter

d

and number density

n

can be expressed as:

$\frac{1}{\sqrt{2} n π d^{2}}$
$\frac{1}{\sqrt{2} n^{2} π d^{2}}$
$\frac{1}{\sqrt{2} n^{2} π^{2} d^{2}}$
$\frac{1}{\sqrt{2} n π d}$

Solution

Mean free path for a gas sample

$λ_{m} = \frac{1}{\sqrt{2} π d^{2} n}$

where $d$ is diameter of a gas molecule and $n$ is molecular density

.

Asked in: NEET 2020 (Phase 1)

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