The mean deviation of the numbers $a, a+d, a+2 d, \ldots, a+2 n d$ from their mean is equal to

The mean deviation of the numbers $a, a+d, a+2 d, \ldots, a+2 n d$ from their mean is equal to
  1. $\frac{(n+1) d}{2 n+1}$
  2. $\frac{n(n+1) d}{2 n+1}$
  3. $\frac{(n+1)|d|}{2 n}$
  4. $\frac{n(n+1)|d|}{2 n+1}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 2)

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