The mean deviation from the mean for the data $6,7,10$, $12,13,4,12,16$ is
The mean deviation from the mean for the data $6,7,10$, $12,13,4,12,16$ is
- $3: 25$
- $3.52$
- $3.33$
- $2.35$
Solution
Mean $=\frac{6+7+10+12+13+4+12+16}{8}=10$
Mean deviation
$
\begin{aligned}
& |6-10|+|7-10|+|10-10|+|12-10|+|13-10| \\
= & \frac{+|4-10|+|12-10|+|16-10|}{8} \\
= & \frac{4+3+0+2+3+6+2+6}{8}=\frac{26}{8}=3.25
\end{aligned}
$
Asked in: AP EAMCET 2023 (19 May Shift 1)
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