The maximum value of the objective function $\mathrm{z}=4 x+6 y$ subject to $3 x+2 y \leq 12, x+y \geq 4, x$…
- 24
- 46
- 56
- 36
Solution

At $A(4,0), Z=4(4)+6(0)=16$ At B( 0,4$), Z=4(0)+6(4)=24$ At $\mathrm{C}(0,6), \mathrm{Z}=4(0)+6(6)=36$ $\therefore \quad \mathrm{Z}$ has maximum value at $\mathrm{C}(0,6)$ which is 36 .
Asked in: MHT CET 2024 (04 May Shift 2)