The maximum value of f ( x ) = sin ( x ) in the interval - π 2 , π 2 is

The maximum value of f(x)=sin(x) in the interval -π2,π2 is
  1. −1
  2. -1
  3. 1
  4. 2

Solution

Drawing the curve of 

fx=sinx

We can see that at x=π2, we get maxima, which is the value fx=1.

Asked in: AP EAMCET 2021 (19 Aug Shift 2)

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