The maximum value of $z=7 x+8 y$ subject to the constraints $x+y \leq 20, y \geq 5, x \leq 10, x \geq 0, y…

The maximum value of $z=7 x+8 y$ subject to the constraints $x+y \leq 20, y \geq 5, x \leq 10, x \geq 0, y \geq 0$ is
  1. $150$
  2. $160$
  3. $110$
  4. $180$

Solution

Feasible region lies on the origin side of lines $x+y=20, x=10$ and on non-origin side of $y=5$. $\therefore \quad$ Corner points of the feasible region are $\mathrm{A}(0,5), \mathrm{B}(10,5), \mathrm{C}(10,10)$ and $\mathrm{D}(0,20)$ $\mathrm{z}$ at $\mathrm{A}(0,5)=40$ $\mathrm{z}$ at $\mathrm{B}(10,5)=110$ $\mathrm{z}$ at $\mathrm{C}(10,10)=150$ $\mathrm{z}$ at $\mathrm{D}(0,20)=160$ $\therefore \quad$ Maximum value of $\mathrm{z}$ is 160 .

Asked in: MHT CET 2023 (12 May Shift 2)

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